-125x^2+700x+1020=0

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Solution for -125x^2+700x+1020=0 equation:



-125x^2+700x+1020=0
a = -125; b = 700; c = +1020;
Δ = b2-4ac
Δ = 7002-4·(-125)·1020
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(700)-1000}{2*-125}=\frac{-1700}{-250} =6+4/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(700)+1000}{2*-125}=\frac{300}{-250} =-1+1/5 $

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